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Q.

If the velocity (v) of a body in time ‘t’ is given by $V = {AT}^{3} + {BT}^{2} + CT + D$ then the dimensions of C are_____

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a

$[{LT}^{- 1}]$

b

$[{LT}^{- 2}]$

c

$[{LT}^{- 3}]$

d

$[{LT}^{- 4}]$

answer is B.

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Detailed Solution

Using principle of homogeneity

Dimensional formula of velocity and CT will be same

$[{LT}^{- 1}] = [C] [T] \Rightarrow [C] = [{LT}^{- 2}]$

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