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If the vertical component of earth's magnetic field is $0.5 \times 10^{- 4}$ T at a point. When an aeroplane of wing span $4 m$ is moving horizontally at this place at $360 {kmh}^{- 1}$ , then the motional emf formed across the ends of the wings is

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$20 \times 10^{- 4} V$

$2 \times 10^{- 4} V$

$20 \times 10^{- 3} V$

$20 \times 10^{- 2} V$

answer is C.

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Detailed Solution

$e = B l v$

$= 0.5 \times 10^{- 4} \times 4 \times 100$

$= 20 \times 10^{- 3} V$

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