If the volume of a sphere is 4851 cm³, then what is its surface area?

Let the radius of the sphere be r.

It is given that the volume of the sphere is 4851 cm³.

We know that, the volume of the sphere = $\frac{4}{3}{\mathrm{\pi r}}^3$

$\Rightarrow \frac{4}{3}{\mathrm{\pi r}}^3=4851$

$\Rightarrow \frac{4}{3}\times \frac{22}{7}{\mathrm{r}}^3=4851$

$\Rightarrow {\mathrm{r}}^3={\left(\frac{21}{2}\right)}^3$

$\Rightarrow \mathrm{r}=\frac{21}{2} \mathrm{cm}$

The surface area of the sphere = $4{\mathrm{\pi r}}^2$

$$\begin{gathered} =4\times \frac{22}{7}\times \frac{21}{2}\times \frac{21}{2} \\ =1386 {\mathrm{cm}}^2 \end{gathered}$$

Thus, the surface area of the sphere is 1386 cm².