If the volume of unit cell of bcc lattice of a metal is 'v' m3. the radius of each metal atom in metres is:

The side length 'a' =V3 and in bcc lattice radius r=a34∴r=V3×34

If the volume of unit cell of bcc lattice of a metal is 'v' m3. the radius of each metal atom in metres is:

The side length 'a' =V3 and in bcc lattice radius r=a34∴r=V3×34

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If the volume of unit cell of bcc lattice of a metal is 'v' m³. the radius of each metal atom in metres is:

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$\frac{1}{2} \times \sqrt[3]{V}$

$\frac{\sqrt{3}}{4} \times \sqrt[3]{V}$

$\sqrt[3]{\frac{V}{4}}$

$\frac{\sqrt{3 V}}{4}$

answer is B.

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The side length 'a' $= \sqrt[3]{V}$ and in bcc lattice radius $r = \frac{a \sqrt{3}}{4}$

$∴ r = \sqrt[3]{V} \times \frac{\sqrt{3}}{4}$

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If the volume of unit cell of bcc lattice of a metal is 'v' m3. the radius of each metal atom in metres is:

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If the volume of unit cell of bcc lattice of a metal is 'v' m³. the radius of each metal atom in metres is: