If the wavelength of electromagnetic radiation is doubled, what happens to the energy of photon?

Energy of photon $\mathrm{E}=\frac{\mathrm{hc}}{\mathrm{\lambda }}\Rightarrow \mathrm{E\alpha }\frac{1}{\mathrm{\lambda }}$,
$\mathrm{\lambda }\to$ wave length of EM radiation
$\frac{{\mathrm{E}}_1}{{\mathrm{E}}_2}=\frac{{\mathrm{\lambda }}_2}{{\mathrm{\lambda }}_1}\Rightarrow \frac{\mathrm{E}}{{\mathrm{E}}_2}=\frac{2\mathrm{\lambda }}{\mathrm{\lambda }}\Rightarrow {\mathrm{E}}_2=\mathrm{E}/2,$ If the wave length of EM radiation is doubled, then the energy of photon becomes halved.