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Q.

If the wavelength of first member of Balmer series of hydrogen spectrum is 6564 A0, the wavelength of second member of Balmer series will be:

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a

6050 A0

b

1215 A0

c

data given is insufficient to calculate the value

d

4862 A0

answer is B.

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Detailed Solution

1λ∝1n12−1n22∴λ1λ2=122−142122−132⇒6564λ2=2720; ∴λ2=4862A∘

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