If the words formed by using the letters of the word ‘AGAIN’ are arranged in the form of dictionary then, 50th word is

Alphabetical order of the word AGAIN is

            A, A, G, I, N

No of words begin with             A = 4!

No of words begin with G           $=\frac{4!}{2!}=12$

No of words begin with I            $=\frac{4!}{2!}=12$

No of words begin with NAAGI = 1

No of words begin with NAAIG = 1

                             Rank of NAAIG $=4!\times 12\times 12\times 1\times 1=50$