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Q.

If the work function of a certain metal is 3.2×10-19J  and it is a illuminated with light of frequency 10×1014Hz,  the maximum kinetic energy of photo electrons would be(h = 6.6×10-34Js)

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a

4.2×1019J 

b

3.4×1019J 

c

5.3×1019J

d

8.5×1019J

answer is A.

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Detailed Solution

hv=w+kE 

kE=hvw

       =6.6×1034×10×10143.2×1019

       =6.6×10193.2×1019

        =3.4×1019J

 

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If the work function of a certain metal is 3.2×10-19J  and it is a illuminated with light of frequency 10×1014Hz,  the maximum kinetic energy of photo electrons would be(h = 6.6×10-34Js)