Q.

If the work function of a metal is 6.63×1019J, the maximum wavelength of the photon required to remove a photoelectron from the metal is_______nm. (Nearest integer)

 [Given : h=6.63×1034Js, and c=3×108ms1 ] 

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answer is 300.

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Detailed Solution

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ϕ=6.63×1019J=hcλ=6.63×1034×3×108λλ=3×107m=300nm

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