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Q.

If the work function of a photo metal is 6.825 eV . Its threshold wavelength will be $(c = 3 \times 10^{8} m / s)$

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a

1200 $\overset{o}{A}$

b

1800 $\overset{o}{A}$

c

2400 $\overset{o}{A}$

d

3600 $\overset{o}{A}$

answer is B.

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Detailed Solution

$λ_{o} = \frac{12375}{6 .825} = 1813 \overset{o}{A} \approx 1800 \overset{0}{A}$

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