If the x-intercept of the line y= mx + 2 is greater than 1/2, then the gradient of the line lies in the interval

Given equation of line is  y = mx + 2
$\Rightarrow \frac{\mathrm{x}}{-\frac{2}{\mathrm{m}}}+\frac{\mathrm{y}}{2}=1$
It is given that x-intercept of the above line is greater than

$\begin{array}{l}\therefore -\frac{2}{\mathrm{m}}>\frac{1}{2}\\ \Rightarrow -\frac{2}{\mathrm{m}}-\frac{1}{2}>0\\ \Rightarrow -\left(\frac{4+\mathrm{m}}{2\mathrm{m}}\right)>0\\ \Rightarrow \frac{4+\mathrm{m}}{2\mathrm{m}}<0\\ \Rightarrow -4<\mathrm{m}<0\end{array}$