Q.

If the kth term in the expansion of 32x2-13x6is independent of x, then the numerically greatest term in the expansion of 32x2-13xk when x=12, is

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a

764

b

2027

c

4081

d

765

answer is C.

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Detailed Solution

32x2-13xk=32x2-13x5 For N.G.T  (n+1) (b)|a|+|b|=(6) 13x32x2+13x=61223+12 =3(7)(6)=187=2.5 T3 is N.G.T T3=C2  5 32x23 -13x2 =(10) 32×493 122=10×827×14                                          =2027

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If the kth term in the expansion of 32x2-13x6is independent of x, then the numerically greatest term in the expansion of 32x2-13xk when x=12, is