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If there are $' n'$ rational numbers between $' a'$ and $' b'$ , where $a < b$ , then
difference $' d'$ between any two consecutive rational numbers is

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\frac{a - b}{n + 1}

\frac{b - a}{n + 1}

\frac{a - b}{n - 1}

\frac{b - a}{n - 1}

answer is C.

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Detailed Solution

If there are

' n'

rational numbers between

' a'

and

' b'

, where

a < b

, then

difference $' d'$ between any two consecutive rational numbers

$d = \frac{b - a}{n + 1}$

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