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If there is a positive error of 50% in the measurement of velocity of body, find the error in the measurement of kinetic energy

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50%

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100%

80%

answer is C.

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Detailed Solution

$E = \frac{1}{2} {mv}^{2}$

$∴ \frac{∆ E}{E} \times 100 = \frac{∆ m}{m} + \frac{2 ∆ v}{v} \times 100;$

$Here, ∆ m = 0 and \frac{∆ v}{v} \times 100 = 50 %;$

$\Rightarrow \frac{∆ E}{E} \times 100 = 2 \times 50 = 100 %$

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