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If there is an error of $\pm 0.04 c m$ in the measurement of the diameter of a sphere when the radius is 10 cm, then the percentage error in the volume of the sphere is

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$\pm 1.0$

$\pm 1.2$

$\pm 0.8$

$\pm 0.6$

answer is D.

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Detailed Solution

$r = 10 c m, δ r = \pm 0.02 \frac{δ r}{r} \times 100 = \pm 0.2 \frac{δ v}{v} \times 100 = 3 \times (\pm 0.2) = \pm 0.6$

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