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Q.

If there is no inter molecular space, the volume occupied by one molecule of water is (density of water=1 gm/ml)

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a

$5.5 \times 10^{- 23} ml$

b

$6.023 \times 10^{- 23} ml$

c

$9.0 \times 10^{- 23} ml$

d

$3 \times 10^{- 23} ml$

answer is C.

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Detailed Solution

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$d = 1 gm / ml 18 ml H_{2} O = 18$

$gm = 1 mole = 6.023 \times 10^{23} molecules$

$1 molecules Vol = \frac{18}{6.023 \times 10^{23}} = 3 \times 10^{- 23} ml$

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