If three coins are tossed simultaneously, then what is the probability of getting exactly two heads?

Given, three coins are tossed simultaneously.

possible number of outcomes = {HHH, HHT, HTH, HTT, TTT, TTH, THT, THH} = 8

favourable number of outcomes of getting two heads together = {HHT, HTH, THH} = 3

 Probability of getting exactly two heads =$\frac{total number of favourable outcomes}{total number of outcomes}$ 

Therefore, the probability of getting exactly two heads, when three coins are tossed simultaneously =$\frac{3}{8}$