If three coins are tossed simultaneously, what is the probability of getting two heads together?

Concept: Probability of getting probability of the occurrence of an event is$P\left(E\right)=\frac{\text{Total number of favorable outcomes}}{\text{Total number of outcomes}}$.

Here, the sample space$=\{\text{TTT},\text{TTH},\text{THT},\text{HTT},\text{THH},\text{HTH},\text{HHT},\text{HHH}\}$

Let E is the event of getting two heads together.

Then, $E=\{\text{THH},\text{HHT},\text{HHH}\}$

Thus, $P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{3}{8}$.

Hence, the probability of getting two heads together when three coins are tossed simultaneously is $\frac{3}{8}$.