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If three vectors acting at a point ‘O’ as shown in the figure keep the particle in equilibrium the value of $θ$ & ‘P’ are

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the value of P is 10N

the value of $θ$ is $60 °$

the value of $θ$ is $90 °$

the value of P is 20N

answer is A, C.

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Detailed Solution

for ‘O’ to be the equilibrium $10 + P \cos θ = 10$

$\Rightarrow P \cos θ = 0 \Rightarrow θ = 90 ° [∵ P \neq 0]$

also $P \sin θ = 20$

$∴ P = 20 N$

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