If $tnx + \tan 2 x + \tan 3 x = tanx \tan 2 x \tan 3 x$ then $|\sin 3 x + \cos 3 x|$ is equal to

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answer is B.

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Detailed Solution

$\tan x + \tan 2 x + \tan 3 x = \tan x \tan 2 x \tan 3 x x + 2 x + 3 x = π \Rightarrow 6 x = π 3 x = \frac{π}{2} |\sin 3 x + \cos 3 x| = |\sin \frac{π}{2} + \cos \frac{π}{2}| = 1$

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