If two cards are selected from a pack of cards, the probability of getting the cards from the same suit is

$\mathrm{n}\left(\mathrm{S}\right)=5_2 {\mathrm{C}}_2$

$\mathrm{E}=$getting the cards from the same suit

$\mathrm{n}\left(\mathrm{E}\right)=4{\mathrm{C}}_1\times 13{\mathrm{C}}_2$

$$\begin{gathered} \mathrm{P}\left(\mathrm{E}\right)=\underline{4\times 13{\mathrm{C}}_2} \\ 52 {\mathrm{C}}_2 \end{gathered}$$

$\mathrm{P}\left(\mathrm{E}\right)=\frac{4\times 13\times 12}{52\times 51}=\frac{4}{17}$