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If two identical coins are tossed once, then the probability of getting no heads is

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\frac{3}{4}

\frac{1}{2}

\frac{2}{3}

\frac{1}{4}

answer is D.

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Detailed Solution

Getting no head means getting tail only.

$∴$ favourable out come $= 1$

And total out comes $= 4$

$∴$ probability $= \frac{1}{4}$ $= \frac{f a v o u a b l e o u t c o m e s}{t o t a l o u t c o m e s}$

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