If two liquids A and B form minimum boiling azeotrope at some specific composition then

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A-B interactions are stronger than those between A-A or B-B

vapour pressure of solution decreases because less number of molecules of only one of the liquids escape from the solution

A-B interactions are weaker than those of between A-A or B-B

vapour pressure of solution increases because more number of molecules of liquids A and B can escape from the solution

answer is B.

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Detailed Solution

If two liquids A and B form minimum boiling azeotrope at some specific composition then A-B interactions are weaker than those of A - A and B -B interactions. It is due to the fact that in case of positive deviation, we get minimum boiling azeotropes, whereas in case of negative deviation we get maximum boiling azeotropes. Moreover due to weak A-B interactions, the molecules of A (or B) will find it easier to escape and hence, vapour pressure of the solution increases.

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