If two numbers are selected randomly from 20 consecutive natural numbers, the probability that the sum of two numbers is even number is $\frac{k_{1}}{k_{2}}$ then the value of K₂-K₁ is

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answer is 10.

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Detailed Solution

$A = event of getting both the numbers are even or both are odd from 20 consecutive integers = 10_{C_{2}} + 10_{C_{2}} P (A) = \frac{2 (10_{C_{2}})}{20_{C_{2}}} = \frac{9}{19} K_{2} - K_{1} = 19 - 9 = 10$

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