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Q.

If two slits in Young's experiment are 0.4 mm apart and fringe width on a screen 200 cm away is 2 mm, the wavelength of light illuminating the slits is [J&K CET 2013]

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a

600 nm

b

400 nm

c

500 nm

d

300 nm

answer is C.

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Detailed Solution

Fringe width, $β = \frac{D λ}{d}$

Given, d = 0.4 mm, D = 200 cm = 2000 mm

$β = 2 mm$

$∴ 2 = \frac{2000 \times λ}{0.4} \Rightarrow λ = 400 nm$

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