If two soap bubbles of different radii are in communication with each other then

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Air flows from the larger bubble into the smaller one until the two bubbles are of equal size

The size of the bubbles remains the same

Air flows from the smaller bubble into the larger one and the larger one grows at the expense of the smaller one

The air flows from the larger into the smaller bubble until the radius of the smaller one becomes equal to that of the larger one and of the larger one equal to that of the smaller one.

answer is C.

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Detailed Solution

Excess of pressure in a soap bubble, $P = \frac{4 T}{r}$ i.e., $P \propto \frac{1}{r}$ therefore pressure in a smaller bubble is more than that of a bigger bubble. When two bubbles of different radii are in communication, then the air flows from higher pressure to lower pressure i.e. from smaller bubble into larger one.

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