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Q.

If two soap bubbles of radius r₁ and r₂ (> r₁) are in contact, the radius of their common interface is:

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a

$r_{1} + r_{2}$

b

$\sqrt{r_{1} r_{2}}$

c

$r_{1} r_{2} / (r_{2} - r_{1})$

d

${(r_{1} + r_{2})}^{2}$

answer is C.

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Detailed Solution

$\frac{4 T}{r} = \frac{4 T}{r_{1}} - \frac{4 T}{r_{2}}$
r is the radius of the interface
$r = \frac{r_{1} r_{2}}{r_{2} - r_{1}} if r_{2} > r_{1}$

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