Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

If two springs S1 and S2 of force constants K1 and K2 respectively are stretched by same force. It is found that more work is done on spring S1 than that on spring  S2 
Statement – I: If stretched to the same extension, work done on S1, will be more than that on S2
Statement – II: The relation between the force constants will be K1<K2

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

Statement – I is true, Statement – II is true. Statement – II is not the correct explanation for Statement – I

b

Statement – I is false, Statement – II is true

c

Statement – I is true, Statement – II is false

d

Statement – I is true, Statement – II is true. Statement – II is correct explanation for Statement – I

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The work done by the external force will be given by W=F×FK=F2K.

Given that more work is done on spring S1 than spring  S2 , F2K1>F2K2K2>K1

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
If two springs S1 and S2 of force constants K1 and K2 respectively are stretched by same force. It is found that more work is done on spring S1 than that on spring  S2 Statement – I: If stretched to the same extension, work done on S1, will be more than that on S2Statement – II: The relation between the force constants will be K1<K2