If u→=a→−b→,v→=a→+b→ and |a→| = |b→| =2, , then |u→×v→|=

u×v=(a−b)×(a+b)=2a×b ∴|u×v|=2|a→×b|=2[a2b2sin2θ]=2(a2b2−a2b2cos2θ)=2[16−(a.b)2]

If u→=a→−b→,v→=a→+b→ and |a→| = |b→| =2, , then |u→×v→|=

u×v=(a−b)×(a+b)=2a×b ∴|u×v|=2|a→×b|=2[a2b2sin2θ]=2(a2b2−a2b2cos2θ)=2[16−(a.b)2]

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If $\vec{u} = \vec{a} - \vec{b}, \vec{v} = \vec{a} + \vec{b}$ and $| \vec{a} | = | \vec{b} | = 2,$ , then $| \vec{u} \times \vec{v} | =$

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$\sqrt{| 4 - {(a . b)}^{2} |}$

$2 \sqrt{| 16 - {(a \cdot b)}^{2} |}$

$\sqrt{| 16 - {(a . b)}^{2} |}$

$2 \sqrt{| 4 - {(a . b)}^{2} |}$

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$u \times v = (a - b) \times (a + b) = 2 a \times b ∴ | u \times v | = 2 | \vec{a} \times b | = 2 \sqrt{[a^{2} b^{2} {sin}^{2} θ]} = 2 \sqrt{(a^{2} b^{2} - a^{2} b^{2} {cos}^{2} θ)} = 2 \sqrt{[16 - {(a . b)}^{2}]}$

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If u→=a→−b→,v→=a→+b→ and |a→| = |b→| =2, , then |u→×v→|=

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If $\vec{u} = \vec{a} - \vec{b}, \vec{v} = \vec{a} + \vec{b}$ and $| \vec{a} | = | \vec{b} | = 2,$ , then $| \vec{u} \times \vec{v} | =$