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Q.

If  u=a2cos2θ+b2sin2θ+a2sin2θ+b2cos2θ  then the difference between the maximum and minimum value of  u2 is given by

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a

2 (a2 + b2)

b

2a2+b2

c

(a + b)2

d

(a – b)2

answer is D.

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Detailed Solution

u2=a2+b2+2a2cos2θ+b2sin2θ×a2sin2θ+b2cos2θ =a2+b2+2sin2θ.cos2θ(a4+b4)+a2b2(sin4θ+cos4θ) =a2+b2+2a2b2+(a2b2)2sin2θ.cos2θ =a2+b2+2a2b2+(a2b2)24sin22θ

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