If $\overline{u}=2\overline{i}-2\overline{j}+3\overline{k}$ and the final velocity is $\overline{v}=2\overline{i}-4\overline{j}+5\overline{k}$ and it is covered in a time of 10 sec, find the acceleration vector

$\overline{u}=2\hat{i}-2\hat{j}+3\hat{k}$

$\overline{v}=2\hat{i}-4\hat{j}+5\hat{k}$

$\text{t}=10\sec$

$\text{a}=?$

$\text{a}=\frac{\left(2\hat{i}-4\hat{j}+5\hat{k}\right)-\left(2\hat{i}-2\hat{j}+3\hat{k}\right)}{10}$

$=\frac{2\hat{i}-4\hat{j}+5\hat{k}-2\hat{i}+2\hat{j}-3\hat{k}}{10}$

$=\frac{-2\hat{j}+2\hat{k}}{10}=\frac{2\left(-\hat{j}+\hat{k}\right)}{10}$

$\overline{a}=\frac{-\hat{j}+\hat{k}}{5}$