If uncertainity in position and momentum are equal, then uncertainty in velocity is

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If uncertainity in position and momentum are equal, then uncertainty in velocity is

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$\sqrt{\frac{h}{π}}$

$\frac{1}{2 m} \sqrt{\frac{h}{π}}$

$\sqrt{\frac{h}{2π}}$

$\frac{1}{m} \sqrt{\frac{h}{π}}$

answer is B.

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Detailed Solution

$Δx \times Δp = \frac{h}{4 π} ∆ x = ∆ p - - given {(∆ p)}^{2} = \frac{h}{4 π} {(∆ v)}^{2} = \frac{h}{4 {πm}^{2}} ∆ v = \frac{1}{2 m} \sqrt{\frac{h}{π}}$

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