If uncertainty in position and velocity are equal then uncertainty in momentum will be?

$\begin{array}{rr} & \mathrm{\Delta x}.\mathrm{\Delta v}=\frac{\mathrm{h}}{4\mathrm{\pi m}}, \mathrm{\Delta x}=\mathrm{\Delta v}, \mathrm{\Delta v}=\sqrt{\frac{\mathrm{h}}{4\mathrm{\pi m}}} \mathrm{\Delta v}=\frac{1}{2}\sqrt{\frac{\mathrm{h}}{4\mathrm{\pi m}}}\\ & \\ & \mathrm{p} = m \mathrm{\Delta v} = \mathrm{m}\cdot \frac{1}{2}\sqrt{\frac{\mathrm{h}}{\mathrm{\pi m}} }\mathrm{ }\mathrm{p}=\frac{1}{2}\sqrt{\frac{\mathrm{mh}}{\mathrm{\pi }}}\end{array}$