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If vapour pressures of pure liquids 'A' & 'B' are 300 and 800 torr respectively at $25^{o} C$ . When these two liquids are mixed at this temperature to form a solution in which mole percentage of ‘B’ is 92, then the total vapour pressure is observed to be 0.95 atm. Which of the following is true for this solution.

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${ΔV}_{mix} > 0$

${ΔH}_{mix} < 0$

${ΔV}_{mix} = 0$

${ΔH}_{mix} = 0$

answer is B.

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Detailed Solution

According to Raoult's law

$P_{T} = (0 .08 \times 300 + 0 .92 \times 800)$ torr

$= (24 + 736)$ torr

= 760 torr = 1 atm

$P_{exp .}$ = 0.95 atm < 1 atm

Hence solution shows negative deviation

so ${ΔH}_{mix} < 0,$ and ${ΔV}_{mix} < 0$ .

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