If vectors AB¯=-3i^+4k^ and AC¯=5i^-2j^+4k^ are the sides of a ∆ABC, then the length of the median through A is

AB+AC=2AD A=2i-2j-8k2 =i-j+4k AD=32

If vectors AB¯=-3i^+4k^ and AC¯=5i^-2j^+4k^ are the sides of a ∆ABC, then the length of the median through A is

AB+AC=2AD A=2i-2j-8k2 =i-j+4k AD=32

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If vectors $\bar{AB} = - 3 \hat{i} + 4 \hat{k}$ and $\bar{AC} = 5 \hat{i} - 2 \hat{j} + 4 \hat{k}$ are the sides of a $∆ ABC,$ then the length of the median through A is

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$\sqrt{14}$

$\sqrt{29}$

$\sqrt{18}$

answer is D.

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$AB + AC = 2 AD A = \frac{2 i - 2 j - 8 k}{2} = i - j + 4 k |AD| = 3 \sqrt{2}$

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If vectors AB¯=-3i^+4k^ and AC¯=5i^-2j^+4k^ are the sides of a ∆ABC, then the length of the median through A is

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If vectors $\bar{AB} = - 3 \hat{i} + 4 \hat{k}$ and $\bar{AC} = 5 \hat{i} - 2 \hat{j} + 4 \hat{k}$ are the sides of a $∆ ABC,$ then the length of the median through A is