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If volume of a drop of water is 0.0018 mL then the number of water molecules present in ten drop of water at room temperature is

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$2 \times 10^{- 3} N_{A}$

$2 \times 10^{- 4} N_{A}$

$10^{- 3} N_{A}$

$10^{- 4} N_{A}$

answer is A.

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Detailed Solution

Mass of a drop of water = 0.0018g
Moles of water = $\frac{0.0018}{18} = 10^{- 4}$ mole
Number of water molecules in one drop $= 10^{- 4} N_{A}$
Number of water molecule in ten drops $= 10 \times 10^{- 4} \times N_{A} = 10^{- 3}$

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