If $W = [\begin{matrix} 1 & 2 & 3 \\ 3 & 2 & 1 \end{matrix}], X = [\begin{matrix} 1 & 0 \\ 2 & - 1 \\ 0 & 2 \end{matrix}]$ and $Y = [\begin{matrix} 0 & 1 \\ - 2 & 5 \end{matrix}]$ then $W X + Y$ is

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$[\begin{matrix} 2 & 5 \\ 3 & 0 \end{matrix}]$

$[\begin{matrix} - 8 & 20 \\ - 8 & 13 \end{matrix}]$

$[\begin{matrix} 0 & 1 \\ 2 & - 3 \\ - 4 & 10 \end{matrix}]$

$[\begin{matrix} 5 & 5 \\ 5 & 5 \end{matrix}]$

answer is A.

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Detailed Solution

$\begin{array}{l} W X = [\begin{matrix} 1 & 2 & 3 \\ 3 & 2 & 1 \end{matrix}] \times [\begin{matrix} 1 & 0 \\ 2 & - 1 \\ 0 & 2 \end{matrix}] = [\begin{matrix} 1 (1) + 2 (2) + 3 (0) & 1 (0) + 2 (- 1) + 3 (2) \\ 3 (1) + 2 (2) + 1 (0) & 3 (0) + 2 (- 1) + 1 (2) \end{matrix}] \\ = [\begin{matrix} 5 & 4 \\ 7 & 0 \end{matrix}] \\ W X + Y = [\begin{matrix} 5 & 4 \\ 7 & 0 \end{matrix}] + [\begin{matrix} 0 & 1 \\ - 2 & 5 \end{matrix}] = [\begin{matrix} 5 & 5 \\ 5 & 5 \end{matrix}] \end{array}$