If work done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of electrons from an initial point where the electric potential is 9 V to a point where the potential is -5 V (The potential in each case is measured relative to a common reference point) is $15 x \times 10^{4}$ J.. Find x.

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answer is 9.

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Detailed Solution

$Δ V = - 14 V Q = - N_{A} e = - (6.02 \times 10^{23}) (1.6 \times 10^{- 19}) = - 9.63 \times 10^{4} S i n c e Δ V = \frac{W}{Q} \Rightarrow W = Q Δ V = (- 9.63 \times 10^{4} C) (- 14 J C^{- 1}) \Rightarrow W = 1.35 \times 10^{6} J = 1.35 M J$

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