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If work done in stretching a wire by $1 m m$ is $2 J$ , the work (in joules) necessary for stretching another wire of same material, but with double the radius and half the length by $1 m m$ is

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Detailed Solution

$K = \frac{A Y}{l}, K^{'} = \frac{4 A Y}{l / 2} = 8 K \frac{U}{2} = \frac{\frac{1}{2} \times 8 K \times Δ l^{2}}{\frac{1}{2} \times K \times Δ l^{2}} \Rightarrow U = 16 J$

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