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Q.

If x  is any real number, then the greatest integer which doesn’t exceed 'x'  is called the integral part of 'x' and will denoted by [x] .

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Detailed Solution

The integral part of xx, denoted by [x][x], is defined as the greatest integer less than or equal to xx. Below are some examples and properties to help understand and solve questions related to the integral part:

Properties of [x][x]:

  1. [x]x<[x]+1[x] \leq x < [x] + 1
    This means xx lies between [x][x] and [x]+1[x] + 1, where [x][x] is the largest integer less than or equal to xx.
  2. If xx is an integer:
    [x]=x[x] = x.
  3. If xx is not an integer:
    [x][x] is the nearest integer less than xx.
  4. For a negative xx:
    [x][x] is the closest integer less than xx.

Examples:

  1. If x=3.7x = 3.7:
    The greatest integer less than or equal to 3.73.7 is 33.
    [3.7]=3[3.7] = 3.
  2. If x=2.3x = -2.3:
    The greatest integer less than or equal to 2.3-2.3 is 3-3.
    [2.3]=3[-2.3] = -3.
  3. If x=5x = 5:
    [5]=5[5] = 5 (since 55 is already an integer).
  4. If x=1.8x = -1.8:
    [1.8]=2[-1.8] = -2.

Typical Questions Involving [x][x]:

1. Evaluate [3.5]+[2.7][3.5] + [-2.7]:

  • [3.5]=3[3.5] = 3
  • [2.7]=3[-2.7] = -3
    Thus, [3.5]+[2.7]=3+(3)=0[3.5] + [-2.7] = 3 + (-3) = 0.

2. Solve [x]+[2x]=6[x] + [2x] = 6:

  • [x]=n[x] = n (where nn is an integer).
  • [2x]=[2n+f][2x] = [2n + f], where ff is the fractional part (0f<10 \leq f < 1).

From the condition [x]+[2x]=6[x] + [2x] = 6:
n+[2n+f]=6n + [2n + f] = 6.

  • Since [2n+f][2n + f] must also be an integer, analyze ff for nn.
  • Solve 6n2n+f<7n6 - n \leq 2n + f < 7 - n.

3. Prove [x]+[x+12]+[x+23]=3[x][x] + [x + \frac{1}{2}] + [x + \frac{2}{3}] = 3[x]:

This can be approached using properties of [x][x], analyzing fractional parts, and proving the equality holds.

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