Q.

 If x= 1 10  and y= 3 8 , then  evaluate x + y, x – y, x × y and x÷y evaluate x + y, x – y, x × y and .


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a

13 41 , 19 42 , 11 80 and 5 16

b

11 40 , 19 40 , 3 80 and 4 15

c

12 39 , 21 41 , 3 80 and 14 15

d

9 40 , 19 43 , 23 80 and 7 15  

answer is B.

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Detailed Solution

Here, we are given that x= 1 10 and y= 3 8 .
We will do the addition by taking the LCM as follows,
x+y= 1 10 + 3 8 x+y= 4+(15) 40 x+y= 11 40
Next, we will do the subtraction by taking the LCM as follows,
xy= 1 10 3 8 xy= 4(15) 40 xy= 4+15 40 xy= 19 40
Next, we will do the multiplication by multiplying the numerators and denominators of the given rational numbers as follows,
x×y= 1 10 × 3 8 = 3 10×8 = 3 80
Now, we will perform the last operation i.e., division by taking the reciprocal of  3 8 as follows,
x÷y= 1 10 × 8 3 x÷y= 1 5 × 4 3 x÷y= 4 5×3 x÷y= 4 15
So, the results of the respective computations are 11 40 , 19 40 , 3 80 and 4 15 .
Hence, the correct option is (2).
 
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 If x= 1 10  and y= −3 8 , then  evaluate x + y, x – y, x × y and x÷y evaluate x + y, x – y, x × y and .