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Q.

If |x|<12, then the coefficient of xr in the expansion of 1+2x(12x)2 is

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a

r.2r

b

(2r1)2r

c

r.22r+1

d

(2r+1)2r

answer is D.

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Detailed Solution

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(1+2x)(12x)2=(1+2x)r=0 r+1Cr2xr

coefficient of xr=1(coefficient of xr)+2x(coefficient of xr-1) 

coefficient ofxr is (r+1)2r+r2r=2r+12r

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