If x 4 −1210102024x4−1=O then x=

Simplify,2x2+8x−12=0⇒x2+4x−6=0x=−4±16+242=−4±402=2−2±102=−2±10

Simplify,2x2+8x−12=0⇒x2+4x−6=0x=−4±16+242=−4±402=2−2±102=−2±10

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If $[\begin{array}{lll} x 4 - 1 \end{array}] [\begin{array}{ccc} 2 & 1 & 0 \\ 1 & 0 & 2 \\ 0 & 2 & 4 \end{array}] [\begin{matrix} x \\ 4 \\ - 1 \end{matrix}] = O$ then $x =$

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$- 2 \pm \sqrt{10}$

$8 \pm \sqrt{5}$

$- 1 + \sqrt{6}$

$3 \pm \sqrt{6}$

answer is C.

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Simplify, $2 x^{2} + 8 x - 12 = 0 \Rightarrow x^{2} + 4 x - 6 = 0$

$x = \frac{- 4 \pm \sqrt{16 + 24}}{2} = \frac{- 4 \pm \sqrt{40}}{2} = \frac{2 (- 2 \pm \sqrt{10})}{2} = (- 2 \pm \sqrt{10})$

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