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Q.

If ƒ(x)=ax7+bx3+cx5  where a,b,cR  and  ƒ(7)=7 then the range of  ƒ(7)+17cosx is _________.

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a

[34,  34]

b

[0,  34]

c

[34,  17]

d

[34,  0]

answer is D.

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Detailed Solution

ƒ(7)+ƒ(7)=-10 ƒ(7)=17 ƒ(7)+17cosx=17+17cosx

Which has range  [34,  0]

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