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Q.

If [x] denotes the greatest integer less than or equal to x then the value of the integral π2π2[[x]sinx]dx is equal to

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a

1

b

0

c

-π

d

π

answer is A.

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Detailed Solution

I=π2π2([x]+[sinx])dx           ...(i)

Using property,      abf(x)dx=abf(a+bx)dxI=π2π2([x]+[sinx])dx                                                    ...(ii)

Add Eqs. (i) and (ii),

2l=π2π2([x]+[x])+([sinx]+[sinx])dx=π2π2(2)dx=2xπ2π2 [[x]+[x]=1, if x1]2I=(2)π2+(2)π2=2π

 I=π

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