If x−1x=10 ,then the value of x2+1x2 is

x−1x=10 Squaring on both sides (x−1x)2=(10)2 x2+1x2−2=100 x2+1x2=102

If x−1x=10 ,then the value of x2+1x2 is

x−1x=10 Squaring on both sides (x−1x)2=(10)2 x2+1x2−2=100 x2+1x2=102

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If $x - \frac{1}{x} = 10$ ,then the value of $x^{2} + \frac{1}{x^{2}}$ is

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Detailed Solution

x - \frac{1}{x} = 10

Squaring on both sides

${(x - \frac{1}{x})}^{2} = {(10)}^{2}$

$x^{2} + \frac{1}{x^{2}} - 2 = 100$

$x^{2} + \frac{1}{x^{2}} = 102$

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If $x - \frac{1}{x} = 10$ ,then the value of $x^{2} + \frac{1}{x^{2}}$ is