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Q.

If $x - \frac{1}{x} = 10$ ,then the value of $x^{2} + \frac{1}{x^{2}}$ is

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a

102

b

100

c

98

d

10

answer is A.

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Detailed Solution

x - \frac{1}{x} = 10

Squaring on both sides

${(x - \frac{1}{x})}^{2} = {(10)}^{2}$

$x^{2} + \frac{1}{x^{2}} - 2 = 100$

$x^{2} + \frac{1}{x^{2}} = 102$

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