If $x$ is a real number and the set of values of ‘ $x$ ’ satisfying the in equality $\frac{x^2+4x+3}{x^3-6x^2+11x-6}>0$  is given by $(a,b)\cup (c,d)\cup (e,\infty )$ then the value of  $2\left|a\right|+3b+2000c-5d+10e$ is 

(where $a<b<c<d<e$ )