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If “x” is the number of ways in which six women and six men can be arranged to sit in a row such that no two women are together and if “y” is the number of ways they are seated around a table in the same manner, then x : y =

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12 : 1

42 : 1

16 : 1

6 : 1

answer is B.

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Detailed Solution

$x = 7! 6! & y = 6! 5! \Rightarrow x : y = 42 : 1$

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