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Q.

If x,y,z[0,1] then

x2+y2+z2xyz+k.

Then find the least positive integral value of k is______

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answer is 2.

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Detailed Solution

Recall that a quadratic function with positive leading coefficient on any interval [α,β]  attains a maximum at either one of the endpoints. Now, consider the function f(x,y,z)=x2+y2+z2-xyz-2. This is quadratic in each of x,y,z, which implies that the maximum of f is obtained when x,y,z0,1. It is easy to check cases to see that the inequality holds.

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