If $x+1$  is a factor of $x^4+(p-3)x-(3p-5)x^2+(2p-9)x+6$ , then the value of p is

x+1 is a factor

$\Rightarrow -1isthezeroofthepolynomial$

$\Rightarrow {(-1)}^4+\left(p-3\right)\left(-1\right)-\left(3p-5\right){\left(-1\right)}^2+\left(2p-9\right)\left(-1\right)+6=0$

$\Rightarrow p=4$